White to move and mate in two
Otto Wurzburg
American Chess Bulletin, September–October, 1939
→ Solution | Solution to the last problem
Source: Howard, K.S. (1961). How to solve chess problems. Second revised edition. New York: Dover Publications, Inc.
this is a great little two mover- Bxg2=stalemate- the obvious Rxg5+ Rxg5(forced) then Kf2 wins- though not in two moves because the rook can still interpose…
Ra4…pawn moves- Ra5#
Close, sir, but no cee-gar. 1. Ra4 is not followed by a pawn move, but by 1…Rg1. White still wins 2. Kf2+ Rg2 3. Bxg2, but not in two!
nice try “beat crime rhyme spree”
1. Bf6 …Rf2 2.Kxf2#
Rh2 2. Rxg5#
Rg3 2. Kxg3#
etc.
1.Bf6 Rg1, protecting g5 and the discovery attack on h1.
1.Ra2
A. 1…Rxa2 2.Rxg5#
B. 1…Rg3 2.Kxg3#
C. 2…Rg4 2.Kxg4#
D. 2…Rh2 2.Rxg5#
E. 2…Rg1 2.Rd2#
Sorry, left out a variation and made notation mistakes. Should be:
1.Ra2
A.1…Rxa2 2.Rxg5#
B. 1…Rg3 2.Kxg3#
C. 1…Rg4 2.Kxg4#
D. 1…Rh2 2.Rxg5#
E. 1…Rg1 2.Rd2#
F. 1…c4 2.Ra5#
what a great two move problem… ofcourse Ra2- process of elimination takes on a new meaning here, nicely done bicycle.
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